What is the pH of a solution created by combining 1.22 mole of HOBr and 0.49...

What is the pH of a solution created by combining 1.22 mole of HOBr and 0.49 mole NaOH in a 1.00L solution? K_{a HOBr} = 2.5 x 10^-9

Expert Solution

HOBr + NaOH -----------> NaOBr + H2O

I 1.22 0.49 0

C -0.49 -0.49 0.49

E 0.73 0 0.49

PKa = -logka

= -log2.5*10^-9

= 8.6

PH = Pka + log[NaOBr]/[HOBr]

= 8.6 + log0.49/0.73

= 8.6-0.173 = 8.427

queen_honey_blossom answered 2 years ago

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