1. a.) What is the pH of a solution created by combining 1.27 mole of HOBr...

1. a.) What is the pH of a solution created by combining 1.27 mole of HOBr and 0.43 mole NaOH in a 1.00L solution? Ka HOBr = 2.5 x 10-9

b.)What is the pH of a buffer made by combining 0.98 moles HOBr with 0.67 moles NaOBr in a 100.00mL solution? Ka HOBr = 2.5 x 10-9

Expert Solution

HOBr + NaOH --------> NaOBr + H₂O

1.27 0.43

1.27 -0.43 0.43 -0.43 =0

= 0.84 0.43 0

Its a buffer solution , acidic buffer

So

pH = pka + log(salt/acid)

= -log(2.5x10^-9 ) + log ( 0.43/0.84)

= 8.6 + (-0.29) = 8.3

b) its a also an acidic buffer solution

pH = pka + log(salt/acid)

= -log(2.5x10^-9 ) + log ( 0.67/0.98)

= 8.6 + (-0.16) = 8.43

queen_honey_blossom answered 2 years ago

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