Question

In: Math

Consider the following sample data for the relationship between advertising budget and sales for Product A:...

Consider the following sample data for the relationship between advertising budget and sales for Product A: Observation 1 2 3 4 5 6 7 8 9 10 Advertising ($) 40,000 50,000 50,000 60,000 70,000 70,000 80,000 80,000 90,000 100,000 Sales ($) 240,000 308,000 315,000 358,000 425,000 440,000 499,000 494,000 536,000 604,000 What is the slope of the "least-squares" best-fit regression line? Please round your answer to the nearest hundredth. Note that the correct answer will be evaluated based on the full-precision result you would obtain using Excel.

Solutions

Expert Solution

Line of Regression Y on X i.e Y = bo + b1 X
X Y (Xi - Mean)^2 (Yi - Mean)^2 (Xi-Mean)*(Yi-Mean)
40000 240000 841000000 33087610000 5275100000
50000 308000 361000000 12973210000 2164100000
50000 315000 361000000 11427610000 2031100000
60000 358000 81000000 4083210000 575100000
70000 425000 1000000 9610000 3100000
70000 440000 1000000 327610000 18100000
80000 499000 121000000 5944410000 848100000
80000 494000 121000000 5198410000 793100000
90000 536000 441000000 13018810000 2396100000
100000 604000 961000000 33160410000 5645100000

calculation procedure for regression
mean of X = sum ( X / n ) = 69000
mean of Y = sum ( Y / n ) = 421900
sum ( (Xi - Mean)^2 ) = 3290000000
sum ( (Yi - Mean)^2 ) = 119230900000
sum ( (Xi-Mean)*(Yi-Mean) ) = 19749000000
b1 = sum ( (Xi-Mean)*(Yi-Mean) ) / sum ( (Xi - Mean)^2 )
= 19749000000 / 3290000000
= 6.0027
bo = sum ( Y / n ) - b1 * sum ( X / n )
bo = 421900 - 6.0027*69000 = 7711.2462
value of regression equation is, Y = bo + b1 X
Y'=7711.2462+6.0027* X          

slope of the equation is 6.0027,
the above equation compare with y = m*x +c here, m is the slope of the equation


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