Question
In: Statistics and Probability
Investigators studying exercise habits in different regions of the country surveyed a simple random sample of...
Investigators studying exercise habits in different regions of the country surveyed a simple random sample of 421 California adults, age 25 - 35, and an independent simple random sample of 377 Massachusetts adults, age 25 - 35.
Among other observations, the investigators noted that
(i) In the CA sample, the average number of hours/week of exercise
was 7.4, with a standard deviation of 3.3;
(ii) In the MA sample, the average number of hours/week of exercise
was 6.7, with a standard deviation of 3.5.
Based on this data, the investigators concluded that CA adults (in this age group) exercise more than MA adults (in this age group).
Use an appropriate test of significance to test the investigators' claim, at the 5% significance level.
(a) State the formal hypotheses in terms of appropriate population parameters.
(b) Find the test statistic and the p-value and explain how you found them (i.e., where the EV and SE come from, what distribution the test statistic follows, etc.)
(c) Summarize your conclusions in terms of the investigators' claim.
Solutions
orchestra answered 1 year agoRelated Solutions
Investigators studying exercise habits in different regions of the country surveyed a simple random sample of...
Investigators studying exercise habits in different regions of
the country surveyed a simple random sample of 421 California
adults, age 25 - 35, and an independent simple random sample of 377
Massachusetts adults, age 25 - 35.
Among other observations, the investigators noted that
(i) In the CA sample, the average number of hours/week of
exercise was 7.4, with a standard deviation of 3.3;
(ii) In the MA sample, the average number of hours/week of
exercise was 6.7, with a...
8. If a simple random sample of 215 students was surveyed, and it was found that...
8. If a simple random sample of 215 students was surveyed, and
it was found that 90 of them have iPhones, what is the 90%
confidence interval estimate of the proportion of all students who
have iPhones?
The publisher of a regional telephone book surveyed a simple random sample of 10 of its...
The publisher of a regional telephone book surveyed a simple
random sample of 10 of its commercial yellow-page ad customers to
determine whether the size of their ads in square inches were
correlated with the proportion of calls to the business that were
generated by the ads.
a. Calculate the correlation coefficient
b. Calculate the coefficient of determination
What percentage of the variation in the proportion of calls
generated by the ad is explained by the size of the ad...
A professor surveyed a simple random sample of undergraduates at his large university. As part of...
A professor surveyed a simple random sample of undergraduates at
his large university. As part of this survey he asked about part
time jobs the students had and the amount the students were paid
per hour. The resulting data is given in the file “pay_survey.txt”
This data is linked from the Moodle.
This data file contains the following variables.
Gender: Male or Female
Year: Year in school as Freshman, Sophomore, Junior or
Senior
Pay: hourly rate of pay in dollars...
A public opinion poll surveyed a simple random sample of 550 voters in Oregon. The respondents...
A public opinion poll surveyed a simple random sample of
550 voters in Oregon. The respondents were asked which political
party they identified with most and were categorized by residence.
Results are shown below. Decide if voting preference is independent
from location of residence. Let α=0.05.
Republican
Democrat
Independent
NW Oregon
85
103
22
SW Oregon
45
66
10
Central Oregon
46
53
9
Eastern Oregon
67
33
11
Enter the test statistic - round to 4 decimal
places.
A public opinion poll surveyed a simple random sample of 1000 voters. Respondents were classified by...
A public opinion poll surveyed a simple random sample of 1000
voters. Respondents were classified by gender (male or female) and
by voting preference (Republican, Democrat, or Independent).
Results are shown in the contingency table below.
VOTING PREFERENCES
Rep
Dem
Ind Row Total
Male
350
075
25
450
Female
275
240
35
550
Column Total
625
315
60
1000
Is there a gender gap? D3 the men's voting preferences differ
significantly from the women's preferences? Use...
The researcher surveyed adults about their exercise habits and experience of pain. 120 people responded to...
The researcher surveyed adults about their exercise habits and
experience of pain. 120 people responded to the survey. The data
were coded so that participants either did (or did not) experience
elevated pain, and also based on whether or not the respondent
indicated more versus less exercise.
Less Exercise
More Exercise
Less Pain
24
11
More Pain
46
39
Conduct the 5 step hypothesis testing procedure to answer the
question of whether there is an association between pain and
exercise...
In a hypothetical country, there are 1,000,000 eligible voters. A simple random sample of size 200...
In a hypothetical country, there are 1,000,000 eligible voters.
A simple random sample of size 200 was chosen to study the
relationship between gender and participation in the last election.
The results are tabulated as follows.
In order to evaluate the null hypothesis that there is no
association between gender and participation in the elections, we
want to use the chi-square test of association. Fill in the
following blanks. Use and for non-integer numerical
values, include 2 digits after the decimal...
In a simple random sample of 1600 people age 20 and over in a certain country,...
In a simple random sample of 1600 people age 20 and over in a
certain country, the proportion with a certain disease was found
to be 0.110 (or 11.0%).
Complete parts (a) through (d) below.
a. What is the standard error of the estimate of the proportion
of all people in the country age 20 and over with the disease? SE
est=Answer______ (Round to four decimal places as
needed.)
b. Find the margin of error, using a 95% confidence level,...
In a simple random sample of 1000 people age 20 and over in a certain country,...
In a simple random sample of 1000 people age 20 and over in a
certain country, the proportion with a certain disease was found
to be 0.160 (or 16.0%). Complete parts (a) through (d)
below.
A. What is the standard error of the estimate of the proportion
of all people in the country age 20 and over with the disease?
B. Find the margin of error, using a 95% confidence level,
for estimating this proportion.
C. Report the 95% confidence...
ADVERTISEMENT
ADVERTISEMENT
Latest Questions
- Why do we need to choose one configurations of strain gauges load cells among many for...
- Which of the following is the most general and pervasive function of attitudes? a. The object-appraisal...
- Write a 2-3 page paper that answers the question, "Who are you?" The paper should be...
- 1. Identify with explanation any FOUR factors to be considered when selecting the location of a...
- 23. In his treatment of friendship in Book 9, why does Aristotle think that benefactors have...
- Research to identify different virtualization platforms. Provide a discussion of any resources that you find or...
- Assume that the 1-year zero-coupon bond is sold at $88.97 and the yields to maturity for...
ADVERTISEMENT