In: Statistics and Probability
A random sample of size 36 is taken from a population having mean 20 and variance 9.What is the probability that the sample meanXwill be at least 21?
Solution :
Given that,
mean = 
 = 20
variance=9
standard deviation = 
 = 
9=3
n=36

= 
=20

= 
 / 
n = 3 / 
36 = 0.5
P(
 > 21) = 1 - P(
<21 )
= 1 - P[(
- 
) / 
< (21-20) /0.5 ]
= 1 - P(z <2 )
Using z table
= 1 - 0.9772
= 0.0228
probability= 0.0228