In: Statistics and Probability
A random sample of size 36 is taken from a population having mean 20 and variance 9.What is the probability that the sample meanXwill be at least 21?
Solution :
Given that,
mean = = 20
variance=9
standard deviation = = 9=3
n=36
= =20
= / n = 3 / 36 = 0.5
P( > 21) = 1 - P( <21 )
= 1 - P[( - ) / < (21-20) /0.5 ]
= 1 - P(z <2 )
Using z table
= 1 - 0.9772
= 0.0228
probability= 0.0228