In: Chemistry
22. The rate constant for a reaction is 4.62 x 10-3 s -1 at 300°C. The activation energy for the reaction is 46 kJ/mol. What is the rate constant at 600°C?
A. 1.28 x 10-1 s -1 <-Answer
B. 4.66 x 101 s -1
C. 9.37 x 10-1 s -1
D. 4.72 x 103 s -1
E. 9.37 x 103 s -1
Please explain the process in many details.
From Ahrrenius equation;
K1 = A*exp(-Ea/(RT1))
K2 = A*exp(-Ea/(RT2))
Note that A and Ea are the same, they do not depend on Temperature ( in the range fo temperature given)
Then
Divide 2 and 1
K2/K1 = A/A*exp(-Ea/(RT2)) / exp(-Ea/(RT1))
Linearize:
ln(K2/K1) = -Ea/R*(1/T2-1/T1)
get rid of negative sign
ln(K2/K1) = Ea/R*(1/T1-1/T2)
for a generic value:
ln(K) = -Ea/R*(1/T) + ln(A)
where:
x-axis = 1/T ; inverse value of absolute temperature
y-axis = ln(K) , natural log of the rate constant
slope = -E/R or Acitvation Energy divided by Ideal Gas Constant
y-intercept = ln(A) ; natural log of the Frequency Factor
Substitute
ln(K2/(4.62*10^-3) = (46000/8.314)*(1/(300+273) - 1/(600+273))
K2 = (4.62*10^-3)*exp(3.31818)
K2 = 0.1275
K = 1.275*10^-1
choose A