In: Math
Eight artists have been asked to rate the visual characteristics of a painting done first by black and white, and then in multicolor.. After each of the paintings is finished, it is rated on a scale from 1 to 5 with 1 being best and 5 being worst. The results of the rating were shown below: Can you conclude that multicolor painting is better than just black and white? (Use α = 0.05.)
| ARTTIST | BLACK AND WHITE | MULTICOLOR | 
| A | 5 | 1 | 
| B | 4 | 2 | 
| C | 1 | 2 | 
| D | 4 | 3 | 
| E | 3 | 1 | 
| F | 4 | 4 | 
| G | 4 | 5 | 
| H | 2 | 3 | 
µd = µ black and white - µmulticolor
Ho :   µd=   0
Ha :   µd <   0
-----------------
| Sample #1 | Sample #2 | difference , Di =sample1-sample2 | (Di - Dbar)² | 
| 5 | 1 | 4.000 | 10.5625 | 
| 4 | 2 | 2.000 | 1.5625 | 
| 1 | 2 | -1.000 | 3.0625 | 
| 4 | 3 | 1.000 | 0.0625 | 
| 3 | 1 | 2.000 | 1.5625 | 
| 4 | 4 | 0.000 | 0.5625 | 
| 4 | 5 | -1.000 | 3.0625 | 
| 2 | 3 | -1.000 | 3.0625 | 
| sample 1 | sample 2 | Di | (Di - Dbar)² | |
| sum = | 27 | 21 | 6 | 23.5 | 
mean of difference ,    D̅ =ΣDi / n =  
0.7500
std dev of difference , Sd =    √ [ (Di-Dbar)²/(n-1) =
   1.8323
std error , SE = Sd / √n =    1.8323   /
√   8   =   0.6478  
   
          
           
   
t-statistic = (D̅ - µd)/SE = (   0.75  
-   0   ) /    0.6478  
=   1.158
          
           
   
Degree of freedom, DF=   n - 1 =   
7          
       
p-value =        0.8575 [excel
function: =t.dist(t-stat,df) ]      
       
Conclusion:     p-value>α , Do not reject null
hypothesis          
there is no enough evidence to conclude that multicolor painting is better than just black and white