Question

How much heat in kilojoules is required to warm 10.0 g of ice, initially at -20.0 ∘C, to steam at 105 ∘C. The heat capacity of ice is 2.09 J/g∘C and that of steam is 1.84 J/g∘C.

Need help solving it.

I got 30.603, but I do not if it is right.

Answer 1

You require heat capacity and enthapy of vaporisation & fusion of water also to solve the problem posted.so i am adding the data from my side .....

The heat capacity of ice is 2.09 J/g∘C and that of steam is 1.84 J/g∘C.

The heat capacity of water is 4.184 J/g∘C, enthalpy of vaporization water , 2260 J/gram,

enthalpy of fusion water , 334 J/gram

Heat needed = heating ice ( -20^o to 0 ^o) + melting ice at 0^o + heating water(0^o to 100^o ) +

                          evaportaing water to vapor at 100^o +   heating vapor ( 0^o to 105^o )

                      = (msΔT)_ice +ΔH_fusionx mass + (msΔT)_water   + ΔH_evap x mass + (msΔT)vapor

                     =   10x2.09x20 + 334x10 + 10x4.184x100 + 2260x10 +10x1.84x5

                      = 30634Joules = 30.634Kj