Question

In: Chemistry

How much heat (in kJ) is required to warm 13.0 g of ice, initially at -10.0...

How much heat (in kJ) is required to warm 13.0 g of ice, initially at -10.0 ∘C, to steam at 114.0 ∘C? The heat capacity of ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C.

Solutions

Expert Solution

1. q1 = mCt

          = 13*2.09*(10) = 271.7J

     q2   = fustion*m    = 333.55*13   = 4336.15J

     q3   = mct

             = 13*4.184*(100)   = 5439.2J

     q4    = heat of vaporisation * m

              = 2260*13   = 29380J

     q5    = mct

              = 13*2.01*(114-100)

              = 365.82J

total heat = q1 + q2+ q3+q4+q5 = 271.7 + 4336.15+5439.2 +29380 + 365.82   = 39792.87J = 39.793KJ

queen_honey_blossom answered 1 year ago
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