In: Statistics and Probability
The length of time, in hours, it takes an "over 40" group of people to play one soccer match is normally distributed with a mean of 2.2 hours and a standard deviation of 0.55 hours. A sample of size n = 80 is drawn randomly from the population. Find the probability that the sample mean is between 2.1 hours and 2.4 hours.
Solution :
Given that,
mean = = 2.2
standard deviation = = 0.55
= / n = 0.55 / 80 = 0.0615
= P[(2.1 - 2.2) /0.0615< ( - ) / < (2.4 - 2.2) / 0.0615)]
= P(-1.63 < Z < 3.25)
= P(Z < 3.25) - P(Z < -1.63)
= 0.9994 - 0.0516
= 0.9978
Probability = 0.9978