Question

In: Statistics and Probability

1. One out of four Americans over age 55 has eaten pizza for breakfast. P(Eaten Pizza)...

1. One out of four Americans over age 55 has eaten pizza for breakfast. P(Eaten Pizza) = 0.25. If a sample of 10 Americans over the age of 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast. Use the binomial formula.

Expert Solution

One out of four Americans over age 55 have eaten pizza for breakfast i.e. P(Eaten Pizza)=0.25=p. Therefore, q=1-p=0.75

Sample of 10 Americans over age 55 is selected at random, n=10.

Let X be the random variable that Americans over age 55 have eaten pizza for breakfast. Therefore, X follows Binomial distribution with parameters n=10 and p=0.25 i.e.

To find: P(at most 3 have eaten pizza for breakfast) i.e .

The probability mass function is given by

Required probability is given as:

The probability that at most 3 have eaten pizza for breakfast is 0.7758751.

orchestra answered 1 year ago

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