Question

-What is the molar mass of acetaminophen, C₈H₉NO₂?

-When balanced with the smallest set of whole numbers, the coefficient of O₂ in the following equation is:

__ C₂H₄ + __ O₂ --------> __ CO₂ + __ H₂O

-When 22.0 g NaCl and 21.0 g H₂SO₄ are mixed and react according to the equation below, which is the limiting reagent?

2NaCl + H₂SO₄ -------> Na₂SO₄ + 2HCl

Answer 1

Molar mass of acetaminophen C8H9NO2 = 8 * 12 + 9 * 1 + 1 * 14 + 2 * 16 = 151 g/mol Answer

where Molar mass of C = 12 H = 1 N =14 O = 16

C2H4 + 3 O2 ------> 2 CO2 + 2 H2O   

Answer is cofficient of O2 is 3

Given

mass of NaCl = 22 g

Mass of H2SO4 = 21g

Molar mass of NaCl = 58.44 g/mol

No. of moles of NaCl = mass /molar mass = 22 g / 58.44 g/mol = 0.376 moles

Molar mass of H2SO4 = 98 g/mol

No. of moles of H2SO4 = mass /molar mass = 21 g / 98 g/mol = 0.2143 moles

according to reaction stoichometry each mole of H2SO4 will react with 2 moles of NaCl

so there should be 2 * 0.2143 = 0.4286 moles of NaCl

but we have only 0.376 moles of NaCl

so NaCl is the limiting reatant