Question

What is the molar mass of C4H10? Enter your answer using dimensions of molar mass.

For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
2N2O5(g)→4NO2(g)+O2(g)

4.99×103molN2O5 Express your answer using three significant figures.

1.011×10−3molN2O5 Express your answer using four significant figures.

Answer 1

molar mass of C4H10:

= 4(molar mass of C) + 10(molar mass of H)

= 4(12.0107) + 10(1.00794) = 48.0428 + 10.00794 = 58.05 g/mol

Therefore, molar mass of C4h10 is 58.05 g/mol

from the balanced equation we can say that

2 mole of N2O5 produces 4 mole of NO2 so

4.99*10^3 mole of N2O5 will produce

= 4.99*10^3 mole of N2O5 *(4 mole of NO2 / 2 mole of N2O5 )

= 9.98*10^3 mole of NO2

Therefore, the number of moles of NO2 produced will be 9.98*10^3 mole of NO2

from the balanced equation we can say that

2 mole of N2O5 produces 4 mole of NO2 so

1.011*10^-3 mole of N2O5 will produce

= 1.011*10^-3 mole of N2O5 *(4 mole of NO2 / 2 mole of N2O5 )

= 2.022*10^-3 mole of NO2

Therefore, the number of moles of NO2 produced will be 2.022*10^-3 mole of NO2