Question

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Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.1000...

Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.1000 M HNO3(aq) after 19.4 mL of the acid have been added. Kb of trimethylamine = 6.5 x 10-5

Correct Answer:

8.30 ± 0.02

Solutions

Expert Solution

millimoles of base = B = 20 x 0.1 = 2

millimoles of H+ = 0.1 x 19.4 = 1.94

B + H+ ---------------------> BH+

2   1.94                                0 -------------> I

0.06   0                             1.94 ------------> E

pOH = pKb + log [BH+ / B]

pOH = 4.19 + log (1.94 / 0.06)

pOH = 5.70

pH + pOH = 14

pH = 8.30

queen_honey_blossom answered 2 years ago
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