Question

In: Chemistry

Describe the preparation of 1L of a 0.1 M phosphate buffer at pH 8.0. The pKa...

Describe the preparation of 1L of a 0.1 M phosphate buffer at pH 8.0. The pKa for the buffer is 6.86

Solutions

Expert Solution

Solution:

The values given in the question are as follows.

Buffer pH = 8.0; pKa = 6.86; Required concentration = 0.1M; and Required volume = 1 L.

We know that the pKa's of phosphoric acid are 2.3, 7.21 and 12.35. Required pH is 8 and pKa is 6.86. This means, monosodium dihydrogen phosphate monohydrate [diprotic (H2PO4-)] and disodium monohydrogen phosphate heptahydrate [monoprotic (HPO42-)] shall be used. Further, consider monosodium dihydrogen phosphate monohydrate as acid (HA) and disodium monohydrogen phosphate heptahydrate as conjugate base (A-).

Step 1: Calculating [A-] / [HA] ratio.

The [A-] / [HA] ratio can be calculated using Handerson Hasselbach equation 1

pH = pKa + log([A-] / [HA]) --------> 1

Substitute the values pf pH & pKa in equation 1.

8.0 = 6.86 + log([A-] / [HA])

log([A-] / [HA]) = 8.0 - 6.86 = 1.14

[A-] / [HA] = antilog1.14

[A- ] / [HA] = 13.804 ---------> 2

Step 2: Calculating required quantity of [A-] & [HA].

Now we know the fold difference between these salts from equation 2. Required molarity of the solution is 0.1M,  and we can calculate the required amount.

[HA] + [A-] = 0.1M    ---------> 3   

From equation 2,  [A-] = 13.804 [HA]    ---------> 4

Substitute equation 4 in equation 3.

[HA] + 13.804 [HA] = 0.1M

(14.804) [HA] = 0.1M

[HA] = 0.00675M

Substitute [HA] value in equation 3.

0.00675M + [A-] = 0.1M

[A-] = 0.1M - 0.00675M = 0.09325M

Hence we need to dissolve 0.00675 mol of [HA] and 0.09325 mol of [A-] in 1 L water. Molar mass of [HA] is 137.99 g / mol and  [A-] is 268.07 g / mol.

Quantity required;

[HA] = (0.00675 mol / 1 L) x 137.99 g / mol = 0.9314 g / L

[A-] = (0.09325 mol / 1L) x 268.07 g / mol = 24.997 g / L

Hence 0.9314g monosodium dihydrogen phosphate monohydrate and 24.997g disodium monohydrogen phosphate heptahydrate is required to prepare 1L of 0.1M phosphate buffer at pH 8.0

Step 3: Buffer preparation procedure.

1. Add about 800 mL of distilled water in a suitable container.

2. Add 0.9314g of NaH2PO4H2O to the container.

3. Add 24.997g of Na2HPO4-7H2O to the solution.

4. Check the pH using a pH meter and adjust the pH as necessary using phosphoric acid or sodium hydroxide solution.

4. Once you have reached the desired pH, add distilled water to bring the total volume of phosphoric acid buffer to 1 L.  


Related Solutions

a. Describe the preparation of 2 liters of 0.1 M Glutamate buffer, pH 10.0. You have...
a. Describe the preparation of 2 liters of 0.1 M Glutamate buffer, pH 10.0. You have available monosodium glutamate (MW=169), 0.5M NaOH and distilled water. Use pka of glutamate 9.67. b. Momentarily distracted by having a piece of old light fixture fall on your head, you add 10ml of the 0.5 HCL to the 2L of buffer. What would be the pH now
a. Describe the preparation of 2 liters of 0.1 M Glutamate buffer, pH 10.0. You have...
a. Describe the preparation of 2 liters of 0.1 M Glutamate buffer, pH 10.0. You have available monosodium glutamate (MW=169), 0.5M NaOH and distilled water. b. Momentarily distracted by having a piece of old light fixture fall on your head, you add 10ml of the 0.5 HCL to the 2L of buffer. What would be the pH now?
a. Describe the preparation of 2 liters of 0.1 M Glutamate buffer, pH 10.0. You have...
a. Describe the preparation of 2 liters of 0.1 M Glutamate buffer, pH 10.0. You have available monosodium glutamate (MW=169), 0.5M NaOH and distilled water. b. Momentarily distracted by having a piece of old light fixture fall on your head, you add 10ml of the 0.5 HCL to the 2L of buffer. What would be the pH now?
Describe the preparation of 40 liters of 0.02 M phosphate buffer, pH 6.9, starting from solid...
Describe the preparation of 40 liters of 0.02 M phosphate buffer, pH 6.9, starting from solid Na3PO4 and 1M HCl. The answer is 131.2 g of Na3PO4 + 1330 mL 1M HCl. Please explain in detail how to get this answer.
Describe the preparation of 40 L 0.02 M phosphate buffer, pH 6.9 starting from Solid KH2PO4...
Describe the preparation of 40 L 0.02 M phosphate buffer, pH 6.9 starting from Solid KH2PO4 and K2HPO4
I want to make up 1L of 50mM phosphate buffer, pH 6.8. I have 1M phosphate...
I want to make up 1L of 50mM phosphate buffer, pH 6.8. I have 1M phosphate buffer, pH 12 and 2M HCl. How will I make up this buffer. Please explain! Thank you.
You wish to dispose of 100 mL of 0.1 M sodium phosphate buffer, pH 4.5. Where...
You wish to dispose of 100 mL of 0.1 M sodium phosphate buffer, pH 4.5. Where will you do this? Select all correct answers in list. Mercury Spill Kit Base Compatible Aqueous Waste Acid Compatible Mercury Waste Sanitary Sewer Acid Compatible Organic Waste Acid Compatible Acutely Hazardous Waste Acid Compatible Aqueous Waste Concentrated Nitric Acid Waste Base Compatible Mercury Waste Organic Solid Waste Base Compatible Acutely Hazardous Waste Inorganic Solid Waste Base Compatible Organic Waste
Describe the preparation of 3.00 L of 0.150 M glycine buffer, pH 8.1, from glycine and...
Describe the preparation of 3.00 L of 0.150 M glycine buffer, pH 8.1, from glycine and 1.00 M NaOH. What mass of glycine is required? The appropriate pKapKa of glycine is 9.6. Apply appropriate significant figures.
Calculate the pH if 10mL of 0.1 M NaOH are added to the buffer made by...
Calculate the pH if 10mL of 0.1 M NaOH are added to the buffer made by mixing 25 mL of 1.0 M CH3COOH and 25 mL of 0.5 M CH3COONa.
Calculate the theoretical buffer capability of 0.1 M CH3COOH/CH3COONa buffer at pH=4.74 and pH=6 (I don't...
Calculate the theoretical buffer capability of 0.1 M CH3COOH/CH3COONa buffer at pH=4.74 and pH=6 (I don't know does the pH value affect so I provide it anyway) pKa of acetic acid is 4.74 To calculate the buffer capability, meansure the change by adding 0.5mL of 1.0M HCl and by adding 0.5mL NaOH to 10 mL of buffer, the capability is then the determined as the molarity of the HCl or NaOH added to the buffer divided by the change of...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT