In: Chemistry
can you find the oxygen in room(Kg) if density of air is 1.225 * 10-3 g/cm3and percent of oxygen in air is 21%
volume of the room : 327.29 m3
Mass (m), Volume(V), Density (d) related through relation,
d = m/V ......all expressed in same type of unit.
m = dV
Given: V = 327.29 m3 = 327.29 x (1m)3 = 327.29 x (100 cm)3 = 327.29 x 106 cm3.
d = 1.225 x 10-3 g/cm3.
Using these values in above formula we get,
m = (1.225 x 10-3 g/cm3) x (327.29 x 106 cm3)
cm3 unit cancell out.
m = 400.9 x 103 g
m = 400.9 Kg ....... (103 g = 1Kg)
Mass of gas in a room is 400.9 Kg.
But % Oxygen composition = 21%.
Hence,
Mass of Oxygen in room = (% Oxygen/100) x Total mass of gas in room
= (21/100) x 400.9
= 84.2 Kg.
There is 84.2 Kg of oxygen in the room.
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