In: Statistics and Probability
Suppose that the lifetimes of light bulbs are approximately normally distributed, with a mean of 57 hours and a standard deviation of 3.5 hours. With this information, answer the following questions. (a) What proportion of light bulbs will last more than 62 hours? (b) What proportion of light bulbs will last 52 hours or less? (c) What proportion of light bulbs will last between 57 and 61 hours? (d) What is the probability that a randomly selected light bulb lasts less than 45 hours? (a) The proportion of light bulbs that last more than 62 hours is nothing. (Round to four decimal places as needed.)
we have given and and let x is the lifetimes of light bulbs and
a) P(x> 62 ) =P (z> (62 - 57)/3.5 ) = 0.0766
0.0766 proportion of light bulbs will last more than 62 hours
b) P(x 52 ) = P (z (52 - 57)/3.5 ) = 0.0766
0.0766 proportion of light bulbs will last 52 hours or less .
c) P (57 x 61) = P (57 - 57)/3.5 z (61- 57)/3.5 )
P (57 x 61) =0.3735
the proportion of light bulbs will last between 57 and 61 hours is 0.3735
d) P(x 45 ) = P (z (45 - 57)/3.5 ) =.0003
the probability that a randomly selected light bulb lasts less than 45 hours is 0.0003