Question

In: Statistics and Probability

How large a sample should be selected so that the margin of error of estimate for...

How large a sample should be selected so that the margin of error of estimate for a 98% confidence interval for p is .03 when the value of the sample proportion obtained from a preliminary sample is .75? n = 2013 n = 876 n = 1990 n = 1132

Expert Solution

Solution,

Given that,

= 0.75

1 - = 1 - 0.75 = 0.25

margin of error = E = 0.03

At 98% confidence level

= 1 - 98%

= 1 - 0.98 =0.02

/2 = 0.01

Z/2 = Z0.01 = 2.33

sample size = n = (Z / 2 / E )2 * * (1 - )

= (2.33 / 0.03)2 * 0.75 * 0.25

= 1131.02

sample size = n = 1132

orchestra answered 2 years ago

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