How large a sample should be selected so that the margin of error of estimate for...

How large a sample should be selected so that the margin of error of estimate for a 98% confidence interval for p is .03 when the value of the sample proportion obtained from a preliminary sample is .75? n = 2013 n = 876 n = 1990 n = 1132

Solutions

Expert Solution

Solution,

Given that,

= 0.75

1 - = 1 - 0.75 = 0.25

margin of error = E = 0.03

At 98% confidence level

= 1 - 98%

= 1 - 0.98 =0.02

/2 = 0.01

Z/2 = Z0.01 = 2.33

sample size = n = (Z / 2 / E )2 * * (1 - )

= (2.33 / 0.03)2 * 0.75 * 0.25

= 1131.02

sample size = n = 1132

orchestra answered 1 year ago

Next > < Previous

Related Solutions

How large a sample should be selected so that the maximum error of estimate for a...

How large a sample should be selected so that the maximum error of estimate for a 95% confidence interval for the population mean is 2.1 Assume the population standard deviation is 10.5.

How large a sample n would we need to estimate p with a margin of error...

How large a sample n would we need to estimate p with a margin of error of 0.05 with 95% confidence?

How large a sample should be selected to provide a 95% confidence interval with a margin...

How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the population standard deviation is 40 . Round your answer to next whole number.

Find the minimum sample size required to estimate a population proportion with a margin of error...

Find the minimum sample size required to estimate a population proportion with a margin of error equal to .04 and a confidence level of 90%. A recent study resulted in a sample proportion of .70. Also determine the minimum sample size if no prior study was done.

find the sample size needed to give a margin of error to estimate a proportion within...

find the sample size needed to give a margin of error to estimate a proportion within plus minus 2% within 99% confidence within 95% confidence within 90% confidence assume no prior knowledge about the population proportion p

Find the point estimate, the standard error, and the margin of error for the given confidence...

Find the point estimate, the standard error, and the margin of error for the given confidence level and values of x and n. x=45, n=97, confidence level 95% (a) Find the point estimate. (b) Find the standard error. (c) Find the margin of error.

How do I find the margin of error with a 98% confidence interval estimate of the...

How do I find the margin of error with a 98% confidence interval estimate of the population mean sales price and population mean number of days to sell for Domestic cars? For Domestic Cars Statistics List Price Sale Price Days to Sell N Valid 200 200 200 Missing 0 0 0 Mean 32.1615 29.7430 32.9050 Median 29.5500 27.5500 31.0000 Std. Deviation 18.31094 18.25088 17.86735 Range 75.00 74.60 69.00

1. If you want a poll to have a margin of error of 2.89%, how large...

1. If you want a poll to have a margin of error of 2.89%, how large will your sample have to be? Round your answer to the nearest whole number. ____ people 2. You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estimation for the population proportion. You would like to be 80% confident that you estimate is within 2% of the true population proportion. How large of...

Explain the difference between the standard error of a sample proportion and the margin of error...

Explain the difference between the standard error of a sample proportion and the margin of error of a confidence interval for a population proportion.

Determine the margin of error for a confidence interval to estimate the population proportion for the...

Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.36 and n=125. a. 90% b. 95% c. 98% a. The margin of error for a confidence interval to estimate the population proportion for the 90% confidence level is _ b. The margin of error for a confidence interval to estimate the population proportion for the 95% confidence level is _ c. The margin of...

Subjects