In: Statistics and Probability
) Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3,300. A random sample of 12 assisted-living facilities had an average rate of $3,690 per month. The standard deviation for this sample was $530. Medicare would like to set ΅ = 0.05. The test statistic for this hypothesis test would be ________.
A) z x = 1.98
B) z x = -1.37
C) t x = -2.16
D) t x = 2.55
Solution:
Given:Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3,300.
thus Mean =
Sample size = n = 12
Sample mean =
Sample standard deviation = s = 530
We have to find the test statistic for this hypothesis test.
Since sample size n is small and population standard deviation is unknown , we use t test
Thus correct answer is: D) t x = 2.55