Question

In: Operations Management

Cranberries can be harvested using either a "wet" method or a "dry" method. Dry-harvested cranberries can...

Cranberries can be harvested using either a "wet" method or a "dry" method. Dry-harvested cranberries can be sold at a premium, while wet-harvested cranberries are used mainly for cranberry juice and bring in less revenue. Fresh Made Cranberry Cooperative must decide how much of its cranberry crop should be harvested wet and how much should be dry harvested. Fresh Made has 5,000 barrels of cranberries that can be harvested using either the wet or dry method. Dry cranberries are sold for $36.50 per barrel and wet cranberries are sold for $15.50 per barrel. Once harvested, cranberries must be processed through several operations before they can be sold. Both wet and dry cranberries must go through dechaffing and cleaning operations. The dechaffing and the cleaning operations can each be run 24 hours per day for the 6-week season (for a total of 1,008 hours). Each barrel of dry cranberries requires 0.18 hours in the dechaffing operation and 0.32 hours in the cleaning operation. Wet cranberries require 0.04 hours in the dechaffing operation and 0.10 hours in the cleaning operation. Wet cranberries must also go through a drying process. The drying process can also be operated 24 hours per day for the 6-week season, and each barrel of wet cranberries must be dried for 0.22 hours.

(a) Develop a linear program that Fresh Made can use to determine the optimal amount of cranberries to dry harvest and wet harvest. (Let W = barrels of cranberries harvested using wet method and D = barrels of cranberries harvested using dry method.)

Max: ________

s.t. total harvest: _________

dechaffing: _______

cleaning: ________

drying: ______

W, D ≥ 0

(b) Solve the linear program in part (a). How many barrels should be dry harvested? How many barrels should be wet harvested? (Round your answers to the nearest integer.)

wet [_______] barrels

dry [_______] barrels

(c) Suppose that Fresh Made can increase its dechaffing capacity by using an outside firm for this operation. Fresh Made will still use its own dechaffing operation as much as possible, but it can purchase additional capacity from this outside firm for $500 per hour. Should Fresh Made purchase additional dechaffing capacity? Why or why not?

(option 1) Each additional hour of dechaffing will only improve revenue by about $485. At $500 per hour it would not be profitable to purchase additional hours.

(option 2) There are about 416 hours of dechaffing capacity which are not being used, so additional capacity is not necessary.

(option 3) There are about 485 hours of dechaffing capacity which are not being used, so additional capacity is not necessary.

(option 4) Each additional hour of dechaffing will only improve revenue by about $416. At $500 per hour it would not be profitable to purchase additional hours.

(d) Interpret the dual value for the constraint corresponding to the cleaning operation. How would you explain the meaning of this dual value to management?

(option 1) Each additional hour of cleaning capacity increases revenues $484.73. This is true for any cleaning capacity value greater than or equal to 523.

(option 2) Each additional hour of cleaning capacity increases revenues $416.00. This is true for any cleaning capacity value between 592 and 1,600.

(option 3) Each additional hour of cleaning capacity increases revenues $5.95. This is true for any cleaning capacity value greater than or equal to 523.

(option 4) Each additional hour of cleaning capacity increases revenues $95.45. This is true for any cleaning capacity value between 592 and 1,600.

Solutions

Expert Solution

Part a.

Subject to:

Let W = barrels of cranberries harvested using wet method and

D = barrels of cranberries harvested using dry method.)

The objective is to maximize the total profit of the product mix.

Max: $15.50W + $36.50D

Subject to:

total harvest: W + D <= 5000

dechaffing: 0.04W + 0.18D <= 1008

cleaning: 0.10W + 0.32D <= 1008

drying: 0.22W <= 1008

W, D ≥ 0

Part b.

The excel model:

Optimal Solution:

W = 2690.909 barrels

D = 2309.091 barrels

Profit = $125,990.91

The sensitivity report:

Variable

Value

Reduced Cost

Original Val

Lower Bound

Upper Bound

W

2690.909

0

15.5

11.406

36.5

D

2309.091

0

36.5

15.5

49.6

Dual Value

Slack/Surplus

Original Val

Lower Bound

Upper Bound

total harvest

5.955

0

5000

3150

6300

dechaffing

0

484.727

1008

523.273

Infinity

Cleaning

95.455

0

1008

592

1600

drying

0

416

1008

592

Infinity

Part c:

According to sensitivity report slack of dechaffing resource is 484.727, it means the dechaffing capacity is not completely utilized and 484.727 hours are unutilized. Since there are capacity left with dechaffing resource, extra hours are not required.

Correct option: (option 3) There are about 485 hours of dechaffing capacity which are not being used, so additional capacity is not necessary.

Part d.

The dual value of the cleaning resource is 95.455. the lower bound of the cleaning hours is 592 hours and upper bound is 1600 hours. Thus the dual value is valid between the cleaning capacity of 592 hours to 1600 hours.

Correct ans:

(option 4) Each additional hour of cleaning capacity increases revenues $95.45. This is true for any cleaning capacity value between 592 and 1,600.


Related Solutions

On dry concrete, a car can decelerate at a rate of 7.00 m/s^2, whereas on wet...
On dry concrete, a car can decelerate at a rate of 7.00 m/s^2, whereas on wet concrete it can decelerate at only 5.00 m/s^2. Find the distances necessary to stop a car moving at 30.0 m/s (about 110km/h) (a) on dry concrete and (b) on wet concrete. (c) Repeat both calculations, finding the displacement from the poiint where the driver sees a traffic light turn red, taking into account his reaction time of 0.500 s to get his foot on...
Following the soxhlet procedure, calculate the % fat content on dry and wet basis of a...
Following the soxhlet procedure, calculate the % fat content on dry and wet basis of a cheese sample considering the following: Weight of dried sample = 2.0251 g Weight of sample + thimble + glass wool = 5.4047 g Weight of defatted sample + thimble + glass wool = 4.4107 g % moisture = 35%
Why is it acceptable to use a clean, wet volumetric flask, instead of a clean, dry...
Why is it acceptable to use a clean, wet volumetric flask, instead of a clean, dry volumetric flask, when you are preparing your standard solutions by dilution? Explain in detail.
You are a genetic counselor. As a genetic counselor, you know: -Dry (as opposed to wet)...
You are a genetic counselor. As a genetic counselor, you know: -Dry (as opposed to wet) earwax is an autosomal recessive trait. -Red-green colorblindness is an X-linked recessive trait. -Sickle-cell anemia is an autosomal recessive trait. -The genes for these traits (see above) are located on different chromosomes. You are counseling a woman and a man, as described below. Question A. The woman is heterozygous for wet earwax. She has red-green colorblindness. What is the woman’s genotype? Question B. What...
1. In general, why is it really wet in Eureka, CA and quite dry in San...
1. In general, why is it really wet in Eureka, CA and quite dry in San Diego, CA? 2. How would you measure net primary production in a bean plant? 3. Is the length of daylight in Bakersfield today different from that at the North Pole? Explain
The surgeon orders for wet-to-dry sterile saline dressing twice a day with iodoform gauze to the...
The surgeon orders for wet-to-dry sterile saline dressing twice a day with iodoform gauze to the wound, covered with the wet-to-dry dressing. Explain how to perform this dressing change?
Air with a dry bulb temperature 75 F and a wet bulb temperature 65 F is...
Air with a dry bulb temperature 75 F and a wet bulb temperature 65 F is at a sea level pressure of 14.7 psia. Using equations to calculate (a) humidity ratio, (b) the relative humidity of the air, (c) enthalpy, (d) dew point, and (e) the mass density of the dry air. (50)
The dry and wet-bulb temperatures of atmospheric air at 95 kPa are 25C and 20C, respectively....
The dry and wet-bulb temperatures of atmospheric air at 95 kPa are 25C and 20C, respectively. Determine (a) the specific humidity, (b) the relative humidity), and (c) the enthalpy of the air in kj/kg dry air.
You purchased a ton of wet hops (75% water by weight), and need to dry them...
You purchased a ton of wet hops (75% water by weight), and need to dry them to 10% water by weight. How much energy is required to drive off the water? How much wood (i.e., mass) do you need to burn (if you ran a 1900's Oast -- hop kiln) in order to drive off the water? You may assume 100% energy efficiency, and the heat of combustion of wood to be Hc = 16,300 kJ/kg
The dry- and wet-bulb temperatures of atmospheric air at 98 kPa are 28 and 14°C, respectively....
The dry- and wet-bulb temperatures of atmospheric air at 98 kPa are 28 and 14°C, respectively. Determine the following values.   1. The specific humidity in  kg H2O/kg dry air 2. The relative humidity in % 3. The enthalpy of air in  kJ/kg dry air
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT