Question

In: Chemistry

Calculate the change of enthalpy for: 4S + 6O2= 4SO3 Delta H= ___ kJ

Calculate the change of enthalpy for: 4S + 6O2= 4SO3 Delta H= ___ kJ

Solutions

Expert Solution

fH0 S (monoclinic) = 0.3 KJ/mol

fH0 O2(g) = 0 KJ/mol

fH0 SO3(g) = -395.7 KJ/mol

H0 = fH0 (Product) - fH0 (Reactant)

H0 = [(4fH0 SO3] - [(4fH0 S) + (6fH0 O2)]

= [(4 (-395.7)) ] - [4(0.3) + (6 (0)]

= [-1582.8] - [1.2]

H0 = -1584 KJ/mol

H0 for reaction = -1584 KJ/mol

queen_honey_blossom answered 1 year ago
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