In: Economics
The business plan for KnowIt, LLC, a start-up company that manufactures portable multigas detectors, showed equivalent annual cash flows of $400,000 for the first 5 years. If the cash flow in year 1 was $307,000 and the constant increase thereafter was $50,000 per year, what interest rate was used in the calculation? The interest rate used in the calculation was
Present Value of Amount payed after n years is given by:
P = A/(1 + r)n
where r = interest rate
We have to find r such that Present Value of both the cash flows are equal
There is annual cash flow of 400,000 for 5 years
Hence In this case we have net Present Value is given by:
NPV = 400,000/(1 + r) + 400,000/(1 + r)2 + 400,000/(1 + r)3 + 400,000/(1 + r)4 + 400,000/(1 + r)5
In second case we have following cash flow 307,000 for 1st year and There is constant increase thereafter was $50,000 per year.
Now NPV' = 307,000/(1 + r) + 357,000/(1 + r)2 + 407,000/(1 + r)3 + 457,000/(1 + r)4 + 507,000/(1 + r)5
Hence equating these we get
NPV = NPV'
=> 400,000/(1 + r) + 400,000/(1 + r)2 + 400,000/(1 + r)3 + 400,000/(1 + r)4 + 400,000/(1 + r)5
= 307,000/(1 + r) + 357,000/(1 + r)2 + 407,000/(1 + r)3 + 457,000/(1 + r)4 + 507,000/(1 + r)5
=> 93,000/(1 + r) + 43,000/(1 + r)2 - 7,000/(1 + r)3 - 57,000/(1 + r)4 - 107,000/(1 + r)5 = 0
Let (1 + r) = t
=> 93,000/t + 43,000/t2 - 7,000/t3 - 57,000/t4 - 107,000/t5 = 0
=> 93,000t4 + 43,000t3 - 7,000t2 - 57,000t - 107,000 = 0
Solving this we get:
t = 1.07267
=> (1 + r) = 1.07267
=> t = 0.07267 ~ 7.267%
Hence,
The interest rate used in the calculation was 7.267%