When 13.63 g (about one tablespoon) of table sugar (sucrose, C12H22O11) is dissolved in 241.5 mL...

When 13.63 g (about one tablespoon) of table sugar (sucrose, C12H22O11) is dissolved in 241.5 mL of water (density 0.997 g/mL), the final volume is 250.0 mL (about one cup). Part A What is the mass percent of the table sugar? Express your answer to three significant figures. % SubmitMy AnswersGive Up Part B What is the molarity of the table sugar? Express your answer to three significant figures. M SubmitMy AnswersGive Up Part C What is the molality of the table sugar? Express your answer to three significant figures. m

Expert Solution

A) we need find mass of water so,

mass of water = density x volume

mass of water = 0.997 g/mL x 241.5 mL = 240.7755 g

mass of table sugar = 13.63 g so,

total mass of solution = sugar + water = ( 13.63 g + 240.7755 g ) = 254.4055 g

mass percent of table sugar = (13.63 g / 254.4055 g) x100 = 5.35758 % ~ 5.36 %

B) molarity = no. of moles of solute / volume of solution (L)

moles of sugar = given mass / molar mass = (13.63 g / 342.2965 g/mol) = 0.0398 moles

molarity of table sugar = 0.0398 moles / 0.2415 L = 0.1648 M ~ 0.165 M

C) molality = no. of moles of solute / mass of solution (kg)

moles of table sugar = 0.0398 moles

mass of solution (water) = 240.7755 g = 0.2407755 Kg

molality of table sugar = 0.0398 moles / 0.2407755 kg = 0.1653 m ~ 0.165 m

queen_honey_blossom answered 2 years ago

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