4.24
Equal volumes of 0.050 M Ba(OH)2 and 0.040
M HCl are allowed to react. Calculate the
molarity of each of the ions present after the reaction.
Answer: 0.025 M
Ba2+ ; 0.020
M HCl- ; [H+] = (approx)
0 ; 0.30 M OH-
Calculate the concentrations of H2SO3, HSO−3, SO2−3, H3O+ and
OH− in 0.020 M H2SO3. [H2SO3], [HSO-3],[SO2-3],[H3O+],[OH-] = ?
Express your answer using two significant
figures.
Consider an amphoteric hydroxide, M(OH)2(s), where M is a
generic metal. M(0H)2 yields M+2OH M(OH)2 +2OH yields (M(OH4)2-
Ksp=3x10^-16 Kf= .05 Estimate the solubility of M(OH)2 in a
solution buffered at pH = 7.0, 10.0, and 14.0.
A 10.0 mL solution of 0.030 M AgNO3 was titrated with 0.015 M
NaBr in the cell. S.C.E. || titration solution | Ag(s) Find the
cell voltage for 0.4, 10.0, 20.0, and 27.0 mL of titrant. (The Ksp
of AgBr = 5.0 ✕ 10−13.) 0.4 V 10.0 V 20.0 V 27.0 V
Calculate the molar solubility, s, of calcium iodate in 0.020 M
Ca(NO3)2, a completely dissociated strong electrolyte. (NO3- ion
does not chemically interact with either Ca2+ or IO3-.) Assume that
Ksp for Ca(IO3)2 = 2.0 x 10^-6.
To set up the problem, we write the following equations:
Material balance for calcium: [Ca2+] = s + 0.020
Material balance for iodate: [IO3-] = 2s
Ksp = 2.0 x 10^-6 = [Ca2+][IO3-]^2 = (s + 0.020)(2s)^2
The last equation only contains one...
Cd (s) + NiO(OH) (s) -> Cd(OH)2 (s) + Ni(OH)2 (not
balanced)
a. Balance the reaction above usingt the 1/2 reaction method, in
alkaline conditions
b.`if 5.00 g of Cd and 7.5 g of NiO(OH) are combined, which will
be the limiting reactant? How much of the other reactant will
remain after the reaction completes?
The expected rate of return on a Treasury Bill is 0.020, the
expected rate of return on the Bud 5000 is 0.08 and the required
rate of return of a stock is 0.10. What is the stocks beta?