In: Chemistry
You add 1 mol of acetic acid (pka 4.76) and 0.5 mol of NaOH to 1 L of water. Find the pH of the solution.
CH3COOH + NaOH -------------> CH3COOH
I 1 0.5 0
C -0.5 -0.5 +0.5
E 0.5 0 0.5
[CH3COOH] = 0.5M
[CH3COONa] = 0.5M
PKa = 4.76
PH = PKa + log[CH3COONa]/[CH3COOH]
= 4.76 + log0.5/0.5
= 4.76 + 0
= 4.76 >>>>answer