In: Statistics and Probability
In a survey of 3,778 adults concerning complaints about restaurants, 1,436 complained about dirty or ill-equipped bathrooms and 1,213 complained about loud or distracting diners at other tables. Complete parts (a) through (c) below.
a. Construct a 90% confidence interval estimate of the population proportion of adults who complained about dirty or ill-equipped bathrooms.
b. Construct a 90% confidence interval estimate of the population proportion of adults who complaied about loud or distracting diners at other tables.
(round to 4 decimal placed)
The confidence interval for population proportion,"p" for any characteristic is given by :
where is the sample proportion ; and
E is the margin of error and
where is the upper point of the standard normal distribution.
a) Dirty or ill-equipped bathrooms
Here we have :
Thus, the required confidence interval is given by:
0.380095 - 0.012990 < p < 0.380095 + 0.012990
0.367105 < p < 0.393085
0.3671 < p < 0.3931 (Rounded to 4 decimal places)
b) Loud or distracting diners at other tables
Here we have:
Thus, the required confidence interval is given by:
0.321069 - 0.012494 < p < 0.321069 + 0.012494
0.308575 < p < 0.333564
0.3086 < p < 0.3336 (Rounded to 4 decimal places)
For any queries, feel free to comment and ask.
If the solution was helpful to you, don't forget to upvote it by clicking on the 'thumbs up' button.