In: Physics
How much heat energy is required to warm up 2.35 kg of water, from 20oC to 83oC ? Need to show unit conversion and all referents in calculation.
We can calculate the amount of heat energy required to warm place up 2.35 kg of water by the formula Q = mc (temperature difference ). The detailed solution is shown below as an image.
So the amount of heat energy required to warm up 2.35 kg of water is 618.85 KJ.
Hope you ok with this and thank you .