In: Physics
How much thermal energy (in joules and calories) must be added to 5.0 kg of pure water at 0°C to raise the temperature to 37°C?
Mass m = 5 kg
Temperature dt = 37 o C - 0 o C = 37 o C
Specific heat of water C = 4186 J / kg o C
Thermal energy added Q = mCdt
=5x4186x37
= 774410 J
= (774410/4.186) cal
= 185000 cal