How much thermal energy (in joules and calories) must be added to 5.0 kg of pure...

How much thermal energy (in joules and calories) must be added to 5.0 kg of pure water at 0°C to raise the temperature to 37°C?

Solutions

Expert Solution

Mass m = 5 kg

Temperature dt = 37 ^o C - 0 ^o C = 37 ^o C

Specific heat of water C = 4186 J / kg ^o C

Thermal energy added Q = mCdt

=5x4186x37

= 774410 J

= (774410/4.186) cal

= 185000 cal

genius_generous answered 1 year ago

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