In: Chemistry
Estimate the value of the equilibrium constant at 505 K for each of the following reactions.
2CO(g)+O2(g)⇌2CO2(g)
2H2S(g)⇌2H2(g)+S2(g)
1.
2 CO(g) + O2(g) ----------------- 2 CO2(g)
G rxn = 2x Gf CO2 - [ 2xGf CO + Gf O2]
= 2x(-394.38) -[ 2x(-137.38 + 0.0]
= -788.76 +274.76
Grxn = -514 KJ
R = 8.314x10^-3 KJ , T = 505 K
Grxn = - RTlnK
Grxn = - 2.303 RTlogk
-514 = -2.303 x 8.314x10^-3 x 505 xlogk
logk = 514/9.669 = 53.16
K = 10^53.16
K= 1.44x10^53
2)
2 H2S(g) ---------------- 2H2(g) + S2(g)
Grxn = [2xGfH2 + G S2]- 2xGf H2S
= 2x0.0+80.08 - [2x(-33.05)]
= 80.88+66.1
= 146.18KJ
Grxn = 146.18KJ
Grxn = - RTlnK
Grxn = - 2.303 RTlogk
146.18 = - 2.303 x 8.314x10^-3x505 xlogk
logk = -146.18/9.669
logK= -15.11
K = 10^-15.11= 7.76x10^-16
K = 7.76x10^-16.