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A gas mixture A composed of 50% ethylene (C2H4) and 50% nitrogen (N2) can be prepared...

A gas mixture A composed of 50% ethylene (C2H4) and 50% nitrogen (N2) can be prepared by blending gas mixture B (20% ethylene and 80% nitrogen by volume) and C (100% ethylene).

If 43.3 L (@98.7 atm and 21.1C) of C is used to make mixture A, how many moles of B are needed? How many moles of A can be obtained?

N2: Tc = 126.2 K, pc = 33.9 bar

C2H4: Tc = 282.8 K, pc = 51.1 bar

1 bar = 0.986 atm

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queen_honey_blossom answered 2 years ago
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