Question

What is the solar azimuth angle at 14h00 (watch time) for Fargo, North Dakota on Aug. 13. Given: Latitude = 46.8°N Use the shorter algorithm for declination. Use whole numbers only for your answer in degrees.

Answer 1

Sun position at a given date. Azimuth and elevation :-

date= 13/08/2018

FORGA, NORTH DAKOTA :- Latitude =46.8⁰ ,Longitude =(-96.78⁰)

## Greenwich, London, UK is 6 hours ahead of Fargo, ND, USA

Sun position=>

Time	Azimuth	Altitude above the horizon
0:00	168.82	48.88
1:00	190.94	48.59
2:00	211.81	45.51
3:00	230.13	39.97
4:00	245.85	32.82
5:00	259.64	24.77
6:00	272.29	16.37
7:00	284.44	8.03
8:00	296.65	0.14
9:00	309.35	-6.93
10:00	322.82	-12.78
11:00	337.19	-17.00
12:00	352.27	-19.22
13:00	7.64	-19.23
14:00	22.73	-17.02
15:00	37.10	-12.81
16:00	50.58	-6.97
17:00	63.28	0.10
18:00	75.49	7.98
19:00	87.64	16.32
20:00	100.28	24.72
21:00	114.07	32.78
22:00	129.78	39.93
23:00	148.08	45.48

## GOOGLE (source)