In: Physics
What is the solar azimuth angle at 14h00 (watch time) for Fargo, North Dakota on Aug. 13. Given: Latitude = 46.8°N Use the shorter algorithm for declination. Use whole numbers only for your answer in degrees.
Sun position at a given date. Azimuth and elevation :-
date= 13/08/2018
FORGA, NORTH DAKOTA :- Latitude =46.80 ,Longitude =(-96.780)
## Greenwich, London, UK is 6 hours ahead of Fargo, ND, USA
Sun position=>
Time | Azimuth | Altitude above the horizon |
---|---|---|
0:00 | 168.82 | 48.88 |
1:00 | 190.94 | 48.59 |
2:00 | 211.81 | 45.51 |
3:00 | 230.13 | 39.97 |
4:00 | 245.85 | 32.82 |
5:00 | 259.64 | 24.77 |
6:00 | 272.29 | 16.37 |
7:00 | 284.44 | 8.03 |
8:00 | 296.65 | 0.14 |
9:00 | 309.35 | -6.93 |
10:00 | 322.82 | -12.78 |
11:00 | 337.19 | -17.00 |
12:00 | 352.27 | -19.22 |
13:00 | 7.64 | -19.23 |
14:00 | 22.73 | -17.02 |
15:00 | 37.10 | -12.81 |
16:00 | 50.58 | -6.97 |
17:00 | 63.28 | 0.10 |
18:00 | 75.49 | 7.98 |
19:00 | 87.64 | 16.32 |
20:00 | 100.28 | 24.72 |
21:00 | 114.07 | 32.78 |
22:00 | 129.78 | 39.93 |
23:00 | 148.08 | 45.48 |
## GOOGLE (source)