Question
In: Statistics and Probability
A random sample of 200 high school students in a particular town showed that 122 smoke...
A random sample of 200 high school students in a particular town showed that 122 smoke on a regular basis. Find the 99% confidence interval estimating the population percentage for smokers at this high school.
Solutions
Expert Solution
Solution :
Given that,
n = 200
x = 122
Point estimate = sample proportion = 
= x / n = 122/200 = 0.610
1 -
= 0-0.610 = 0.390
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
Z/2
= Z0.005 = 2.576
Z/2
= 2.576
Margin of error = E = Z
/ 2 * 
* (1 -
)) / n)
= 2.576 * (
= 0.089
A 99% confidence interval for population proportion p is ,
- E < p <
+ E
0.610-0.089 < p < 0.610+0.089
0.521 < p < 0.699
( 0.521. 0.699 )
orchestra answered 1 year agoRelated Solutions
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