Question

In: Statistics and Probability

A survey of 600 high school students in our stat showed that 216 felt unsafe in...

A survey of 600 high school students in our stat showed that 216 felt unsafe in their local school. Construct a 95% confidence interval for the proportion of students who felt unsafe.

Expert Solution

Solution :

Given that,

Point estimate = sample proportion = = x / n = 216 / 600 = 0.360

1 - = 1 - 0.360 = 0.64

Z/2 = 1.96

Margin of error = E = Z / 2 * $\sqrt$ (( * (1 - )) / n)

= 1.96 * ( $\sqrt$ ((0.360 * 0.64) / 600)

Margin of error = E = 0.038

A 95% confidence interval for population proportion p is ,

- E < p < + E

0.360 - 0.038 < p < 0.360 + 0.038

0.322 < p < 0.398

The 95% confidence interval for the population proportion p is : 0.322 , 0.398

orchestra answered 2 years ago

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