In: Statistics and Probability
A survey of 600 high school students in our stat showed that 216 felt unsafe in their local school. Construct a 95% confidence interval for the proportion of students who felt unsafe.
Solution :
Given that,
Point estimate = sample proportion =
= x / n = 216 / 600 = 0.360
1 -
= 1 - 0.360 = 0.64
Z/2
= 1.96
Margin of error = E = Z
/ 2 *
((
* (1 -
)) / n)
= 1.96 * (((0.360
* 0.64) / 600)
Margin of error = E = 0.038
A 95% confidence interval for population proportion p is ,
- E < p <
+ E
0.360 - 0.038 < p < 0.360 + 0.038
0.322 < p < 0.398
The 95% confidence interval for the population proportion p is : 0.322 , 0.398