Question

In: Statistics and Probability

Associate’s Degree Bachelor’s Degree $10.75 $10.75 $11.25 $12.25 $11.05 $11.60 Associate’s Degree Bachelor’s Degree $10.00 $9.80...

Associate’s Degree

Bachelor’s Degree

$10.75

$10.75

$11.25

$12.25

$11.05

$11.60

Associate’s Degree

Bachelor’s Degree

$10.00

$9.80

$9.70

$9.40

$11.00

$12.60

$10.10

$11.80

$9.40

$10.40

$9.20

$11.90

$11.10

$12.70

A social researcher is interested in understanding the effect of college education on wages. Listed below are the hourly wages for two groups of employees all working in the same position at a particular technology firm. The workers in one group have earned an associate’s degree while members of the other group hold at least a bachelor’s degree. Test the null hypothesis that there are no differences in mean wages by degrees held by employees. What assumptions about the data must be made to use this test?

Solutions

Expert Solution

Ho :   µ1 - µ2 =   0                  
Ha :   µ1-µ2 ╪   0                  
                          
Level of Significance ,    α =    0.05                  
                          
Sample #1   ---->   1                  
mean of sample 1,    x̅1=   10.355                  
standard deviation of sample 1,   s1 =    0.7657                  
size of sample 1,    n1=   10                  
                          
Sample #2   ---->   2                  
mean of sample 2,    x̅2=   11.320                  
standard deviation of sample 2,   s2 =    1.1653                  
size of sample 2,    n2=   10                  
                          
difference in sample means =    x̅1-x̅2 =    10.3550   -   11.3   =   -0.97  
                          
pooled std dev , Sp=   √([(n1 - 1)s1² + (n2 - 1)s2²]/(n1+n2-2)) =    0.9860                  
std error , SE =    Sp*√(1/n1+1/n2) =    0.4409                  
                          
t-statistic = ((x̅1-x̅2)-µd)/SE = (   -0.9650   -   0   ) /    0.44   =   -2.189
                          
Degree of freedom, DF=   n1+n2-2 =    18                  

p-value =        0.0421   (excel function: =T.DIST.2T(t stat,df) )              
Conclusion:     p-value <α , Reject null hypothesis                      
                          
There is enough evidence to conclude that there is a differences in mean wages by degrees held by employees.

Assumption:

population of two samples have equal variance

two population are normally distributed


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