Question

PleaSe write a GENERATOR function in Python: how to write it with yield ?

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Thanks in advance

Write /the/ generator /function/ genAccum(seq, fn), which takes in an iterable and a function fn and yields each accumulated value from applying fn to the running total and the next element. (Note: to convert an iterable into an iterator you use iter(iterable))

'''
>>> add = lambda x, y: x + y
>>> mul = lambda x, y: x * y
>>> list(genAccum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], add))
[1, 3, 6, 10, 15, 21, 28, 36, 45, 55]
>>> list(genAccum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], mul))
[1, 2, 6, 24, 120, 720, 5040, 40320, 362880, 3628800]
'''

Answer 1

Program Code to Copy:

# genAccum function with yield
def genAccum(seq, fn):
    # Initializing current value to first value
    curr = seq[0]
    # Yielding the current value
    yield curr
    # Running a loop from second value to last value
    for i in range(1, len(seq)):
        # Updating current value by applying fn to current value and element at current index
        curr = fn(curr, seq[i])
        # Yielding the current value
        yield curr


add = lambda x, y: x + y
mul = lambda x, y: x * y
print(list(genAccum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], add)))
print(list(genAccum([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], mul)))

Program Code Screenshot with Output: