Question

In: Computer Science

Python: How would I write a function that takes a directory and a size in bytes,...

Python: How would I write a function that takes a directory and a size in bytes, and returns a list of files in the directory or below that are larger than the size.

For example, I can use this function to look for files larger than 1 Meg below my Home directory.

Expert Solution

CODE:

from os import listdir

from os.path import isfile, join

from os import stat

def getLargeFiles(dirPath, data_size):

#collecting the names of those that are only files

onlyfiles = [f for f in listdir(dirPath) if isfile(join(dirPath, f))]

for file in onlyfiles:

stats = stat(file)

#you can remove this line

print(stats.st_size)

#removing the files that are less in data_size

if stats.st_size <= data_size:

onlyfiles.remove(file)

return onlyfiles

#i have 2 files : 1file 660 bytes and another 597 bytes

print(getLargeFiles("/home/amrit/Projects/Semester/",650))

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refer here for output and indentation

venereology answered 1 year ago

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