Question

In: Chemistry

Fluorine is so reactive that it forms compounds with materials inert to other treatments. When 0.622...

Fluorine is so reactive that it forms compounds with materials inert to other treatments. When 0.622 g of platinum is heated in fluorine, 0.985 g of a dark red, volatile solid forms.

When 0.378 g of this red solid reacts with 0.161 g xenon gas, 0.539 g of an orange-yellow solid forms. What is the empirical formula of this product, the first to contain a noble gas?

Solutions

Expert Solution

Molar Mass of Platinum = 195.084g/mol

Mass of Platinum = 0.622g

No of mole of Platinum = 0.622g/195.084g = 0.003188g

Mass of dark red compound = 0.985g

Mass of Flourine reacted = 0.985g - 0.622g = 0.363g

Molar mass of Flourine = 18.998g

No of mole of Florine reacted = 0.363g / 18.998g = 0.019107

Ratio of flourine / platinum

Flourine / Platinum = 0.019107/0.003188= 5.993 = 6

So , the empirical formula of dark red compound is PtF6 ( Platinum hexaflouride )

Molar mass of PtF6 = 309.07g/mol

Mass of PtF6 reacted = 0.378g

No of mole of PtF6 reacted = 0.378g/309.07g =0.001223

Mass of Xe gas reacted = 0.161g

Molar mass of Xe = 131.296g/mol

No of mole of Xe gas reacted = 0.161g/131.296g = 0.001226

Ratio of PtF6/Xe is 1:1

Therefore ,

the empirical formula is XePtF6 ( Xenon hexaflouroplatinate )

  


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