In: Chemistry
Fluorine is so reactive that it forms compounds with materials inert to other treatments. When 0.622 g of platinum is heated in fluorine, 0.985 g of a dark red, volatile solid forms.
When 0.378 g of this red solid reacts with 0.161 g xenon gas, 0.539 g of an orange-yellow solid forms. What is the empirical formula of this product, the first to contain a noble gas?
Molar Mass of Platinum = 195.084g/mol
Mass of Platinum = 0.622g
No of mole of Platinum = 0.622g/195.084g = 0.003188g
Mass of dark red compound = 0.985g
Mass of Flourine reacted = 0.985g - 0.622g = 0.363g
Molar mass of Flourine = 18.998g
No of mole of Florine reacted = 0.363g / 18.998g = 0.019107
Ratio of flourine / platinum
Flourine / Platinum = 0.019107/0.003188= 5.993 = 6
So , the empirical formula of dark red compound is PtF6 ( Platinum hexaflouride )
Molar mass of PtF6 = 309.07g/mol
Mass of PtF6 reacted = 0.378g
No of mole of PtF6 reacted = 0.378g/309.07g =0.001223
Mass of Xe gas reacted = 0.161g
Molar mass of Xe = 131.296g/mol
No of mole of Xe gas reacted = 0.161g/131.296g = 0.001226
Ratio of PtF6/Xe is 1:1
Therefore ,
the empirical formula is XePtF6 ( Xenon hexaflouroplatinate )