In: Computer Science
Given that , Mileage of vehicle = 10705 miles/gallon
mass of fuel as m = 100 gms of ethanol = 0.1 kg of ethanol
specific gravity = 0.789
density of fuel= specific gravity X density of water = 0.789 X 1000 kg / m^3 = 789 kg / m^3
Volume of fuel stored in the vehicle in m^3 = m / d = 1.267 X 10-4 m3
Since 1m^3 = 264.172 gallons
Hence volume of fuel in gallons = 1.267 X 10-4 X 264.172 = 0.0335 gallons
Distance covered by the vehicle in miles, = Mileage of vehicle X volume of fuel in gallons
= 10705 X 0.0335 = 358.42 miles
Distance covered by the vehicle in kilometres = (distance in miles) X 1.609
= 358.42 X 1.609km = 567.7 km