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In: Computer Science

Can someone do this python program? Write a function that takes a number as a parameter...

Can someone do this python program?

Write a function that takes a number as a parameter and then prints out all of the factors for that number.

Solutions

Expert Solution

The above question can be solved by iterating over all the numbers upto sqrt(n) where n is the number whose factors are to be found. If any number i divides n, then i and n/i are the two factors of the number. In case the number is a perfect square then, the factor i where i*i = n needs to be printed only once. The code is given below:

import math

def factors(n):

i=1#Initialize

while i<=sqrt(n):

if (n%i==0):#Incase i divides n

if(n/i==i):#If i is the square root of n

print(i)#print the factors

else:

print(i)#print the factors

print(int(n/i))#print the factors

i = i+1

if __name__=="__main__":

factors(100)

Sample Run:

Alternate solution:

We could also change the condition in the while loop to i*i<=n. The code is given below:

def factors(n):

i=1#Initialize

while i*i<=n:

if (n%i==0):#Incase i divides n

if(n/i==i):#If i is the square root of n

print(i)#print the factors

else:

print(i)#print the factors

print(int(n/i))#print the factors

i = i+1

if __name__=="__main__":

factors(100)

Sample Run:

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In case of any doubts or queries, please write in comments.:)

venereology answered 10 months ago

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