Many descriptions about matter-antimatter asymmetry starts with the statement that observed baryon to photon density (about 6.1x10^(-10)) is too small. What is the reason? What ratio is expected?

The angular position of a point on the rim of a rotating wheel is given by θ = 3.38t - 2.46t2 + 2.61t3, where θ is in radians and t is in seconds. What are the angular velocities at (a) t = 1.17 s and (b) t = 9.53 s? (c) What is the average angular acceleration for the time interval that begins at t = 1.17 s and ends at t = 9.53 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval?

QUESTION 7 (6 + 6 = 12 marks)
(a) With the aid of appropriate diagrams, explain the following three polarization mechanisms amongst
dielectric materials: (i) electronic, (ii) ionic and (iii) orientational.
(b) For diamond, solid KCl, and liquid Hg (mercury) what kind(s) of polarization (e.g. electronic, ionic
and/or orientation) is (are) possible?

In a Compton scattering experiment, an x-ray photon scatters through an angle of 16.6

Ironman steps from the top of a tall building. He falls freely from rest to the ground a distance of h. He falls a distance of h/ 4 in the last interval of time of 1.0 s of his fall.

Hint: First, compute the velocity when Ironman reaches the height equal to the distance fallen. This requires that you do the following: define origin as the bottom of the building. Then use x-x0 = -v0*(t-t0)-(1/2)g(t-t0)^2 where x=0 and x0= (distance fallen) and t-t0 is the time interval given. In this formulation, you are going to get magnitude of v0 since you already inserted the sign. You then insert v0 that you just calculated into the kinematic equation that involves v, g, and displacement (v^2-v0^2 = 2g(height-(distance fallen)), but now v (which is the final velocity is v0 from above) and v0 in this case is the velocity that the Ironman has when he begins to fall, which is 0. This gives a quadratic equation for height h, and you will need to use the binomial equation to solve for h. Choose the larger of the two solutions.

Part A

What is the height h of the building?

Express your answer using two significant figures.

Two 10-cm-diameter charged rings face each other, 15 cm apart. The left ring is charged to − 30 nC and the right ring is charged to + 30 nC.

What is the magnitude of the electric field E⃗  at the midpoint between the two rings?

What is the direction of the electric field E⃗  at the midpoint between the two rings?

What is the magnitude of the force on a proton at the midpoint?

An object is excuting simple harmonic motion. Which is a true statement regarding its motion?

a. its velocity is never zero

b. its acceleration is never zero

c. its velocity and accelertation are simultaneously zero

d. its velocity is zero when tis acceleration is a maximum

e. its acceleration is maximum when its velocity is maximum

A hollow sphere is rolling along a horizontal floor at 7.00 m/s when it comes to a 31.0 ∘ incline.

How far up the incline does it roll before reversing direction?

Express your answer with the appropriate units.

At what speed does the momentum of a particle differ by 2.00% from the value obtained with the nonrelativistic expression mv?

two plastic curved rods, one of charge q and the other of charge -q. which form a semicircle of radius r=8cm in xy. If q=3.8pC, what would be the magnitud and direction of the electric force E produced in P,in the center.

%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c1%2522%250Axml%253Alang%253D%2522EN-US%2522%253EI%253C%252Fspan%253E%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c1%2522%250Axml%253Alang%253D%2522EN-US%2522%253E%253Cbr%2520%252F%253E%253C%252Fspan%253E%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c1%2522%250Axml%253Alang%253D%2522EN-US%2522%253E%253Cbr%2520%252F%253E%253C%252Fspan%253E%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c1%2522%250Axml%253Alang%253D%2522EN-US%2522%253Envestigation%2520A.%2520The%2520pith%2520ball%250AElectroscope%253C%252Fspan%253E%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2520%2526nbsp%253B%2526nbsp%253B%2520%2526nbsp%253B%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2520c3%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253EThe%2520pith%2520ball%2520electroscope%2520consists%2520of%2520a%2520light%252C%2520conducting%250Apith%2520ball%2520suspended%2520from%2520a%2520support%2520by%2520means%2520of%2520an%2520insulating%250Astring.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c1%2522%250Axml%253Alang%253D%2522EN-US%2522%253E%2526nbsp%253B%253C%252Fspan%253E%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520class%253D%2522c1%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c1%2522%250Axml%253Alang%253D%2522EN-US%2522%253E%2526nbsp%253B%253C%252Fspan%253E%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253EQ1.%2520%2526nbsp%253BA.%2520Ground%2520the%2520pith%2520ball%2520by%2520touching%250Ait.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2520%2526nbsp%253B%2526nbsp%253BB.%2520Rub%2520a%2520rubber%2520rod%2520with%2520wool%2520of%250Afur%2520and%2520bring%2520it%2520near%2520the%2520pith%2520ball%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520C.%2520Remove%2520the%2520rod%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253EQ2.%2526nbsp%253B%2520A.%2520Ground%2520the%2520pith%2520ball.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520B.%2520Rub%2520a%2520glass%2520rod%2520with%2520silk%2520and%250Abring%2520it%2520near%2520the%2520pith%2520ball.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520C.%2520Remove%2520the%2520rod%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253EQ3.%2526nbsp%253B%2520A.%2520Ground%2520the%2520pith%2520ball.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520B.%2520Bring%2520a%2520negatively%2520charged%2520rod%250Anear%2520the%2520pith%2520ball.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520C.%2520Touch%2520the%2520pith%2520ball%2520with%2520the%250Arod%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253EQ4.%2526nbsp%253B%2520A.%2520Charges%2520the%2520pith%2520ball%2520as%2520in%25203%252C%2520by%250Acontact.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520B.%2520Bring%2520a%2520negatively%2520charged%2520rod%250Anear%2520the%2520pith%2520ball.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520C.%2520Removes%2520the%2520rod.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253EQ5.%2526nbsp%253B%2520A.%2526nbsp%253B%2520Charge%2520the%2520pith%2520ball%2520as%2520in%25203%252C%2520by%250Acontact.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520B.%2526nbsp%253B%2520Bring%2520a%2520positively%250Acharged%2520rod%2520near%2520the%2520pith%2520ball.%253C%252Fspan%253E%253C%252Fp%253E%250A%253Cp%2520class%253D%2522MsoNormal%2522%253E%253Cspan%2520lang%253D%2522EN-US%2522%2520class%253D%2522c2%2522%2520xml%253Alang%253D%250A%2522EN-US%2522%253E%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2526nbsp%253B%2520C.%2526nbsp%253B%2520Remove%2520the%250Arod.%253C%252Fspan%253E%253C%252Fp%253E%250A

A 2.50 kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0300 m . The spring has force constant 835 N/m . The coefficient of kinetic friction between the floor and the block is 0.41 . The block and spring are released from rest and the block slides along the floor. Part A What is the speed of the block when it has moved a distance of 0.0130 m from its initial position? (At this point the spring is compressed 0.0170 m .)

A 110cm3 box contains helium at a pressure of 2.00atm and a temperature of 100?C. It is placed in thermal contact with a 210cm3 box containing argon at a pressure of 4.00atm and a temperature of 420?C.

What is the initial thermal energy of each gas?

What is the final thermal energy of each gas?

How much heat energy is transferred, and in which direction?

What is the final temperature?

What is the final pressure in each box?