In: Statistics and Probability
Referring to this data:
2.58 2.51 4.04 6.43 1.58 4.32 2.2 4.19
4.79 6.2 1.52 1.38 3.87 4.54 5.12 5.15
5.5 5.92 4.56 2.46 6.9 1.47 2.11 2.32
6.75 5.84 8.8 7.4 4.72 3.62 2.46 8.75
Suppose we can only pass the quality test if there is evidence to suggest that the true mean ignition time is more than 0.04 seconds (or 4 hundredths of a second). please show work.
a. What is the null hypothesis for this test?
b. What is the alternative?
c. Conduct this hypothesis test at α=0.05 using the normal distribution. State all parts, including the critical value, test statistic, and conclusion in context of the problem.
d. Conduct this hypothesis test at α=0.05 using the t-distribution. State all parts, including the critical value, test statistic, and conclusion in context of the problem. Does your conclusion change?
SOLUTION-
WE USE MINITAB-16 FOR THE COMPUTATION PURPOSE
TO COMPUTE STANDARD DEVIATION FOR THE SAMPLE-
ENTER THE SAMPLE> STAT> BASIC STATISTICS> DISPLAY BASIC STATISTICS> UNDER 'STATISTICS', SELECT 'STANDARD DEVIATION'> OK
THE STANDARD DEVIATION = 2.104
1.) THE NULL HYPOTHESIS IS ,
2.) THE ALTERNATE HYPOTHESIS IS ,
3.) PERFORMING A ONE SAMPLE-Z TEST-
STAT> BASIC STATISTICS> ONE SAMPLE-Z> SELECT THE SAMPLE> SET STANDARD DEVIATION IS 2.104> SET THE HYPOTHESIZED MEAN AS 0.04> UNDER 'OPTIONS', SET THE CONFIDENCE LEVEL AS 95.0 AND ALTERNATE AS 'GREATER THAN'> OK
THE TEST STATISTIC IS 11.66 AND THE CORRESPONDING P-VALUE IS 0.000
AS P-VALUE<0.05, WE REJECT THE NULL HYPOTHESIS AND CONCLUDE THAT MEAN TIME IS MORE THAN 0.04
4.) PERFORMING A ONE SAMPLE-T TEST-
STAT> BASIC STATISTICS>ONE SAMPLE-T> SELECT THE SAMPLE> SET THE HYPOTHESIZED MEAN AS 0.04> UNDER 'OPTIONS', SET THE CONFIDENCE LEVEL AS 95.0 AND ALTERNATE AS 'GREATER THAN'> OK
THE TEST STATISTIC IS 11.66 AND THE CORRESPONDING P-VALUE IS 0.000
AS P-VALUE<0.05, WE REJECT THE NULL HYPOTHESIS AND CONCLUDE THAT MEAN TIME IS MORE THAN 0.04
****IN CASE OF DOUBT, COMMENT BELOW. ALSO LIKE THE SOLUTION, IF POSSIBLE.