In: Statistics and Probability
Let x be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood) after a 12-hour fast. Assume that for people under 50 years old, x has a distribution that is approximately normal, with mean μ = 56 and estimated standard deviation σ = 25. A test result x < 40 is an indication of severe excess insulin, and medication is usually prescribed.
(a) What is the probability that, on a single test, x < 40? (Round your answer to four decimal places.)
- What is the probability that x < 40? (Round your answer to four decimal places.)
(c) Repeat part (b) for n = 3 tests taken a week apart. (Round your answer to four decimal places.)
(d) Repeat part (b) for n = 5 tests taken a week apart. (Round your answer to four decimal places.)
(e) Compare your answers to parts (a), (b), (c), and (d). Did the probabilities decrease as n increased?
Solution :
Given that ,
mean = = 56
standard deviation = = 25
a) P(x < 40) = P[(x - ) / < (40 - 56) / 25]
= P(z < -0.64)
Using z table,
= 0.2611
b) n = 2
= = 56
= / n = 25/ 2 = 17.68
The probability distribution of x is approximately normal with μx = 56 and σx = 17.68
P( < 40) = P(( - ) / < (40 - 56) / 17.68)
= P(z < -0.90)
Using z table
= 0.1841
c) n = 3
= = 56
= / n = 25/ 3 = 14.43
The probability distribution of x is approximately normal with μx = 56 and σx = 14.43
P( < 40) = P(( - ) / < (40 - 56) / 14.43)
= P(z < -1.11)
Using z table
= 0.1335
d) n = 5
= = 56
= / n = 25/ 5 = 11.18
The probability distribution of x is approximately normal with μx = 56 and σx = 11.18
P( < 40) = P(( - ) / < (40 - 56) / 11.18)
= P(z < -1.43)
Using z table
= 0.0764
e) yes,