In: Statistics and Probability
Let x be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood) after a 12 hour fast. Assume that for people under 50 years old, x has a distribution that is approximately normal, with mean μ = 86 and estimated standard deviation σ = 35. A test result x < 40 is an indication of severe excess insulin, and medication is usually prescribed.
(d) Repeat part (b) for n = 5 tests taken a week apart. (Round your answer to four decimal places.)
Solution :
Given that,
mean =
= 86
standard deviation =
=35
P( x < 40)
P ( x -
/
) < ( 40 - 86 / 35)
P ( z < -46/ 35 )
P ( z < -1.31)
Using z table
=0.0951
Probability = 0.0951
d) n = 5
= u =86
=
/
n =35/
5
= 15.6525
P (
< 40 )
P (
-
/
)
< (40 - 86 / 15.6525)
P ( z < - 46/ 15.6525 )
P ( z < -2.94 )
Using z table
= 0.0016
Probability = 0.0016