In: Statistics and Probability
Let x be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood) after a 12 hour fast. Assume that for people under 50 years old, x has a distribution that is approximately normal, with mean μ = 84 and estimated standard deviation σ = 29. A test result x < 40 is an indication of severe excess insulin, and medication is usually prescribed.
(a) What is the probability that, on a single test, x
< 40? (Round your answer to four decimal places.)
(b) Suppose a doctor uses the average x for two tests
taken about a week apart. What can we say about the probability
distribution of x? Hint: See Theorem 6.1.
The probability distribution of x is not normal.The probability distribution of x is approximately normal with μx = 84 and σx = 29. The probability distribution of x is approximately normal with μx = 84 and σx = 20.51.The probability distribution of x is approximately normal with μx = 84 and σx = 14.50.
What is the probability that x < 40? (Round your answer
to four decimal places.)
(c) Repeat part (b) for n = 3 tests taken a week apart.
(Round your answer to four decimal places.)
(d) Repeat part (b) for n = 5 tests taken a week apart.
(Round your answer to four decimal places.)
(e) Compare your answers to parts (a), (b), (c), and (d). Did the
probabilities decrease as n increased?
YesNo
Explain what this might imply if you were a doctor or a nurse.
The more tests a patient completes, the stronger is the evidence for lack of insulin.The more tests a patient completes, the stronger is the evidence for excess insulin. The more tests a patient completes, the weaker is the evidence for excess insulin.
a) X represents the glucose
level
X follows normal distribution with μ = 84 and σ =
29
To find P(X <
40)
We use Excel function NORM.DIST to find the
probability
P(X < 40) = NORM.DIST(40, 84, 29,
TRUE)
= 0.0646
P(X < 40) =
0.0646
b) X represents the average glucose
level
for n = 2
By Central Limit Theorem, the correct answer
is
The probability distribution of x is approximately normal with μx =
84 and σx = σ/√n
σx = 29/√2 = 20.5061 =
20.51
Answer :
The probability distribution of x is approximately normal
with μx = 84 and σx =
20.51
P(X < 40) = NORM.DIST(40, 84, 20.51,
TRUE)
= 0.01597
P(X < 40) =
0.0646
c) X represents the average glucose
level
for n = 3
By Central Limit Theorem, the correct answer
is
The probability distribution of x is approximately normal with μx =
84 and σx = σ/√n
σx = 29/√3 =
16.74
Answer :
The probability distribution of x is approximately normal
with μx = 84 and σx =
16.74
P(X < 40) = NORM.DIST(40, 84, 16.74,
TRUE)
= 0.0043
P(X < 40) = 0.0043
d) X represents the average glucose
level
for n = 5
By Central Limit Theorem, the correct answer
is
The probability distribution of x is approximately normal with μx =
84 and σx = σ/√n
σx = 29/√5 =
12.97
Answer :
The probability distribution of x is approximately normal
with μx = 84 and σx =
12.97
P(X < 40) = NORM.DIST(40, 84, 12.97,
TRUE)
= 0.00035
P(X < 40) =
0.00035
e) We have following probabilities for different
n
n | Probability |
2 | 0.0646 |
3 | 0.0043 |
5 | 0.00035 |
We can see that Probability decreases as n
increases
Answer :
YES
f) This implies
The more tests a patient completes, the weaker is the
evidence for excess
insulin.