In: Mechanical Engineering
Determine the response of a mass-spring system when it is subjected to a half-sine pulse of 250 dyne amplitude and 0.25? seconds duration. The mass is 20gm and the spring stiffness is 197.4 dynes/cm.
given data:
mass spring system subjected to half sine pulse having
time duration T=0.25 sec
mass of spring = 20gm
spring stiffness = 197.4 dynes/cm=197.4 gm/sec2
need to find out
?
1 dyne =gm.cm/sec2= Newton
natural frequency
=
m/s
frequency =
m/sec
=
=3.14
=
=4
=.785 which is less than 1.
as we know when the resonance frequency is less than natural frequency system is in oscillation conditaion