Question

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O . Suppose 3.3 g of hydrochloric acid is mixed with 1.44 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

HCl + NaOH -------> NaCl + H2O

molecular wt of HCl = 36.5

molecular wt of HCl = 40

molecular wt of NaCl = 58.4

molecular wt of H2O = 18

HCl + NaOH -------> NaCl + H2O

1 mole equivalent of HCl, reacts with 1 mole equivalent NaOH, and produce 1 mole equivalent o NaCl and one mole equivalent HO or Water.

that means 36.5 g of HCl, reacts with 40 g of NaOH, and produce 58.4 g NaCl and 18 g Water.

So 3.3 g of hydrochloric acid is mixed with 1.44 g of sodium hydroxide, that means

3.3 g of HCl is equal to 0.178 moles. (mole = mass/ molecular weight)

1.44 g of sodium hydroxide equal to 0.036 moles.

So 0.036 moles of NaOH reacts with 0.036 moles of HCl to produce 0.036 moles of NaCl and 0.036 moles of Water.

0.036 moles of wate equals to how much weight of water?

mole = mass/ molecular weight

0.036 = mass/ 18

mass = 0.036*18 = 0.648 g

maximum mass of water that could be produced by the above chemical reaction is 0.648 grams.