Question

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 30.3 g of hydrochloric acid is mixed with 51. g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer 1

mass of HCl = 30.3 g

moles of HCl = 30.3 / 36.45 = 0.831 mol

mass of NaOH = 51. g

moles of NaOH = 51 / 40 = 1.275 mol

HCl (aq)   +   NaOH (aq)   ----------> NaCl (aq) + H2O (l)

1                     1                                                        1

0.831            1.275                                

here limiting reagent is HCl.

moles of H2O formed = 0.831 mol

maximum mass of water produced = 0.831 x 18.02

maximum mass of water produced = 14.97 g

maximum mass of water produced = 15.0 g