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Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride...

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 30.3 g of hydrochloric acid is mixed with 51. g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Solutions

Expert Solution

mass of HCl = 30.3 g

moles of HCl = 30.3 / 36.45 = 0.831 mol

mass of NaOH = 51. g

moles of NaOH = 51 / 40 = 1.275 mol

HCl (aq)   +   NaOH (aq)   ----------> NaCl (aq) + H2O (l)

1                     1                                                        1

0.831            1.275                                

here limiting reagent is HCl.

moles of H2O formed = 0.831 mol

maximum mass of water produced = 0.831 x 18.02

maximum mass of water produced = 14.97 g

maximum mass of water produced = 15.0 g


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