In: Statistics and Probability
Suppose that in past years the average price per square foot for warehouses in the United States has been $32.28. A national real estate investor wants to determine whether that figure has declined now. The investor hires a researcher who randomly samples 49 warehouses that are for sale across the United States and finds that the mean price per square foot is $31.67, with a sample standard deviation of $1.29. At 5% level of significance, test to see if the average price per square foot for warehouses in the U.S. has declined. Interpret your result
The provided sample mean is and the known population standard deviation is, and the sample size is n = 49
The following null and alternative hypotheses need to be tested:
Ho: μ=32.28
Ha: μ≠32.28
This corresponds to a two-tailed test, for which a z-test for one mean, with known population standard deviation will be used.
Based on the information provided, the significance level is α=0.05, and the critical value for a two-tailed test is
zc=1.96.
The z-statistic is computed as follows:
Since it is observed that ∣z∣=3.31>zc=1.96, it is then concluded that the null hypothesis is rejected.
Using the P-value approach: The p-value is p = 0.0009, and since p=0.0009<0.05, it is concluded that the null hypothesis is rejected.
It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the population mean μ is different than 32.28, at the 0.05 significance level.
Confidence Interval
The 95% confidence interval is 31.309<μ<32.031.
The critical value of z is - 1.96 and +1.96.
The critical value is z = ± 1.96 for a two-tailed test at
5% level of significance. Since, the computed value of z= -2.1
falls in rejection region, we reject the null hypothesis. Hence,
the average price per square foot for warehouses has changed
now.