Question

1a. Given: mean difference between men and women = 2.2; standard error of mean difference = 0.8; n men = 61, n women = 61.

Test the following null hypothesis at a=.05

Ho: u men = u women

Ha: u men > u women

You need to compute the t statistic, look up t critical value and make decision including likelihood of appropriate error. You don't have to compute the standard error of mean difference because it's given.

1b. Compute the appropriate confidence interval for the two-sample t-test of the previous question. Make sure you look at the alternative hypothesis before computing this interval.

Please upload into a Microsoft Word file and show work for answers

For 1b. please show work by doing step by step. line margins

Answer 1

ANSWER::

we have given mean difference between men and women() = 2.2;

standard error of mean difference(SE)= 0.8;

nm = 61, n w = 61.

Ho: u men = u women

Ha: u men > u women

1a ) t = () / SE = 2.2/0.8 = 2.75

t at 0.05 with 120 df (one tailed ) = 1.657

since t calculated >1.657 so we reject Ho

1b ) t at 0.05 with 120 df (two tailed ) = 1.98 ( for constructing Confidence interval)

95%CI = () +/- t*SE = 2.2 +/- 1.98*0.8

= 2.2+/-1.584

= (0.616,3.784)

since confidence interval do not contain 0 so we reject Ho

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